2x^2-4400=0

Solution for 2x^2-4400=0 equation:

2x^2-4400=0

a = 2; b = 0; c = -4400;
Δ = b2-4ac
Δ = 02-4·2·(-4400)
Δ = 35200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{35200}=\sqrt{1600*22}=\sqrt{1600}*\sqrt{22}=40\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{22}}{2*2}=\frac{0-40\sqrt{22}}{4}
=-\frac{40\sqrt{22}}{4}
=-10\sqrt{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{22}}{2*2}=\frac{0+40\sqrt{22}}{4}
=\frac{40\sqrt{22}}{4}
=10\sqrt{22}
$